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¿Cómo encontrar el registro anterior [n-per-group max(timestamp)

El último enfoque con variables es razonable. También puede probar:

SELECT collect.*,
       (select max(timestamp)
        from data
        where data.channel_id = collect.channel_id AND data.timestamp < collect.timestamp
       ) AS prev_timestamp
FROM data AS collect 
WHERE collect.channel_id = 14 AND collect.timestamp >= 0 
ORDER BY collect.timestamp;

Además, cree índices en:collect(channel_id, timestamp).

EDITAR:

Los siguientes podrían ser los más rápidos:

  select d.*,
         if(@channel_id = channel_id, @prev_timestamp, NULL) as prev_timestamp,
         @channel_id := channel_id, @prev_timestamp = timestamp
  from data d cross join
       (select @channel_id := 0, @prev_timestamp := 0) vars
  where collect.channel_id = 14 AND collect.timestamp >= 0 
  order by channel_id, timestamp;