Al mirar sus capturas de pantalla, parece que se está duplicando según la cantidad de etiquetas en cada ubicación. Esto sería desde la combinación de etiquetas para poder filtrar las ubicaciones. Al agregar un distintivo a su consulta, eliminará los valores duplicados de la base de datos. Después de hacer eso, probablemente querrá volver a mostrar valores duplicados, ya que no se mostrará si realiza la misma cantidad y valor de compras para una pieza determinada.
SELECT DISTINCT costlayer.qty AS Qty, costlayer.orgqty, costlayer.orgtotalcost,
costlayer.totalcost AS TotalCost, costlayer.datecreated AS DateCreated,
part.num AS PartNumber, part.description as PartDescription, asaccount.name as "InventoryAccount",
company.name AS company, currency.symbol
FROM CostLayer
LEFT JOIN Part ON part.id = costlayer.partid
LEFT JOIN Tag ON part.id = tag.partId
LEFT JOIN Location ON tag.locationId = location.id
LEFT JOIN LocationGroup ON location.locationGroupId = locationGroup.id
LEFT JOIN asaccount ON part.inventoryaccountid = asaccount.id
JOIN company ON company.id = 1
LEFT JOIN currency ON currency.homeCurrency = 1
WHERE costlayer.datecreated BETWEEN $P{dateRange1} AND $P{dateRange2}
AND costlayer.statusid IN ($P!{ckShowActiveCostingLayers},$P!{ckShowFulfilledCostingLayers},$P!{ckShowVoidedCostingLayers})
AND UPPER(part.num) LIKE UPPER($P{partNum})
AND (UPPER(COALESCE(asaccount.name,'')) LIKE UPPER('%' || $P{AssetAccount} || '%'))
AND LocationGroup.id LIKE $P{locationGroupID}
ORDER BY (CASE WHEN $P{AssetAccount} NOT LIKE CAST('%' AS varchar(256)) THEN asaccount.name ELSE part.num END), part.num ASC, costlayer.id, costlayer.datecreated
