Usando PIVOT puede hacer lo siguiente
With SampleData AS
(
SELECT 'Team1' as Team , 'example@sqldat.com' as email, 'A' as Groups
UNION SELECT 'Team1' as Team , 'example@sqldat.com' as email, 'B' as Groups
UNION SELECT 'Team1' as Team , 'example@sqldat.com' as email, 'C' as Groups
UNION SELECT 'Team2' as Team , 'example@sqldat.com' as email, 'A' as Groups
UNION SELECT 'Team2' as Team , 'example@sqldat.com' as email, 'B' as Groups
UNION SELECT 'Team2' as Team , 'example@sqldat.com' as email, 'C' as Groups
)
SELECT Team, A, B,C FROM
(SELECT * FROM SampleData) source
PIVOT
(MAX(email) FOR Groups IN ([A], [B], [C]) )as pvt
Produce
Team A B C
----- ---------------- ---------------- ----------------
Team1 example@sqldat.com example@sqldat.com example@sqldat.com
Team2 example@sqldat.com example@sqldat.com example@sqldat.com
Vea un ejemplo de Data.SE en funcionamiento
En una base de datos que no es compatible con PIVOT, puede realizar múltiples combinaciones en su tabla. Aunque es posible que desee hacerlo de todos modos, ya que, como señaló GBN, ya que no estamos utilizando un agregado.
With SampleData AS
(
SELECT 'Team1' as Team , 'example@sqldat.com' as email, 'A' as Groups
UNION SELECT 'Team1' as Team , 'example@sqldat.com' as email, 'B' as Groups
UNION SELECT 'Team1' as Team , 'example@sqldat.com' as email, 'C' as Groups
UNION SELECT 'Team2' as Team , 'example@sqldat.com' as email, 'A' as Groups
UNION SELECT 'Team2' as Team , 'example@sqldat.com' as email, 'B' as Groups
UNION SELECT 'Team2' as Team , 'example@sqldat.com' as email, 'C' as Groups
)
SELECT
source.Team,
A.email,
B.email,
C.email
FROM
(SELECT DISTINCT TEAM From SampleData) source
LEFT JOIN SampleData A
ON source.Team = A.Team
AND A.GROUPS = 'A'
LEFT JOIN SampleData B
ON source.Team = B.Team
AND B.GROUPS = 'B'
LEFT JOIN SampleData C
ON source.Team = C.Team
AND C.GROUPS = 'C'
Vea un ejemplo de Data.SE