Lo siguiente genera una tabla de turnos. No está exactamente claro lo que desea hacer, pero debería poder realizar ingeniería inversa para determinar el cambio de la fecha/hora de un evento utilizando algunos de los cálculos que se muestran aquí.
EDITAR :case corregido para manejar al patrón 2/2/3/2.
; with Samples as (
-- Start at the beginning of 2013.
select Cast( '01-01-2013 00:00' as DateTime ) as Sample
union all
-- Add hours up to the desired end date.
select DateAdd( hour, 1, Sample )
from Samples
where Sample <= '2013-01-30'
),
ExtendedSamples as (
-- Calculate the number of days since the beginning of the first shift on 1/1/2013.
select Sample, DateDiff( hour, '01-01-2013 07:00', Sample ) / 24 as Days
from Samples ),
Shifts as (
-- Calculate the shifts for each day.
select *,
case when ( Days + 1 ) % 9 in ( 0, 1, 4, 5 ) then 'C/D' else 'A/B' end as Shifts
from ExtendedSamples )
select *,
case when DatePart( hour, Sample ) between 7 and 18 then Substring( Shifts, 1, 1 ) else Substring( Shifts, 3, 1 ) end as Shift
from Shifts
option ( maxrecursion 0 )
