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Extraiga columnas de la tabla derivada y súmelas en una declaración SELECT de MySQL

Tuve un error ortográfico y un problema de formato. Al formatear los datos finales en lugar de formatear dentro de la instrucción SELECT incrustada, los datos de mi tabla eran precisos.

CÓDIGO exitoso:

$sql = "SELECT x.company, x.stagestatus, x.shippeddate, FORMAT(SUM(x.totprice), 2) as totalprice, FORMAT(SUM(x.sgtotquantity), 2) as sgtotqty, FORMAT(SUM(x.sgtotalsqft), 2) as sgtotsqft, FORMAT(SUM(x.avgsqftrev), 2) as avgsqftrevenue, FORMAT(SUM(x.avgunitrev), 2) as avgunitrevenue FROM (SELECT t1.company, t1.stagestatus, t1.shippeddate, t1.id, TRIM(LEADING '$' FROM t1.totalprice) AS totprice, t2.invoiceid, SUM(t2.quantity) AS sgtotquantity, SUM(t2.width * t2.height * t2.quantity ) /144 AS sgtotalsqft, (TRIM(LEADING '$' FROM t1.totalprice)/(SUM(t2.width * t2.height * t2.quantity ) /144)) as avgsqftrev, (TRIM(LEADING '$' FROM t1.totalprice) / SUM(t2.quantity)) AS avgunitrev
FROM invoices AS t1 INNER JOIN lineitems AS t2 ON t1.id = t2.invoiceid
WHERE (t2.invoiceid = t1.id)
GROUP BY t1.id) x
WHERE x.stagestatus='Complete'
GROUP BY x.company ASC";

¡¡¡Gracias!!!