Actualizar e incrementar múltiples columnas en duplicado

Dado que las columnas no aceptan valores NULL, debe pasar 0 s en lugar de null s para las columnas que no desea proporcionar valores en INSERT declaraciones y comparaciones de uso con 0 en lugar de null :

INSERT INTO stock (price, stock1, stock2) VALUES
  ('99', '10', 0), 
  ('120', 0, '12')
ON DUPLICATE KEY UPDATE 
  `stock1-C` = `stock1-C` + (VALUES(stock1) <> 0 AND stock1 <> 0),
  stock1 = stock1 + VALUES(stock1), 
  `stock2-C` = `stock2-C` + (VALUES(stock2) <> 0 AND stock2 <> 0),
  stock2 = stock2 + VALUES(stock2)

Resultado:

Entonces otra vez:

INSERT INTO stock (price, stock1, stock2) VALUES
  ('99', '10', 0), 
  ('120', 0, '12')
ON DUPLICATE KEY UPDATE 
  `stock1-C` = `stock1-C` + (VALUES(stock1) <> 0 AND stock1 <> 0),
  stock1 = stock1 + VALUES(stock1), 
  `stock2-C` = `stock2-C` + (VALUES(stock2) <> 0 AND stock2 <> 0),
  stock2 = stock2 + VALUES(stock2)

Resultado:

Entonces:

INSERT INTO stock (price, stock1, stock2) VALUES
  ('150', '55', 0), 
  ('150', 0, '56')
ON DUPLICATE KEY UPDATE 
  `stock1-C` = `stock1-C` + (VALUES(stock1) <> 0 AND stock1 <> 0),
  stock1 = stock1 + VALUES(stock1), 
  `stock2-C` = `stock2-C` + (VALUES(stock2) <> 0 AND stock2 <> 0),
  stock2 = stock2 + VALUES(stock2)

Resultado:

Entonces:

INSERT INTO stock (price, stock1, stock2) VALUES
  ('150', '10', 0), 
  ('150', 0, '10')
ON DUPLICATE KEY UPDATE 
  `stock1-C` = `stock1-C` + (VALUES(stock1) <> 0 AND stock1 <> 0),
  stock1 = stock1 + VALUES(stock1), 
  `stock2-C` = `stock2-C` + (VALUES(stock2) <> 0 AND stock2 <> 0),
  stock2 = stock2 + VALUES(stock2)

Resultado:

Vea la demostración .