Esta es una buena manera, nombre elegante "método Tabibitosan " dada por Aketi Jyuuzou.
SQL> WITH data AS
2 (SELECT num - DENSE_RANK() OVER(PARTITION BY status ORDER BY num) grp,
3 status,
4 num
5 FROM t
6 )
7 SELECT MIN(num)
8 ||' - '
9 || MAX(num) range,
10 COUNT(*) cnt
11 FROM data
12 WHERE status='A'
13 GROUP BY grp
14 ORDER BY grp
15 /
RANGE CNT
------ ----------
1 - 3 3
6 - 6 1
9 - 10 2
SQL>
Nota Es mejor usar DENSE_RANK para evitar duplicados.
Mesa
SQL> SELECT * FROM t ORDER BY num;
NUM S
---------- -
1 A
1 A
2 A
2 A
3 A
4 U
5 U
6 A
7 U
8 U
9 A
NUM S
---------- -
10 A
12 rows selected.
Hay duplicados para num =1.
Uso de DENSE_RANK :
SQL> WITH data AS
2 (SELECT num - DENSE_RANK() OVER(PARTITION BY status ORDER BY num) grp,
3 status,
4 num
5 FROM t
6 )
7 SELECT MIN(num)
8 ||' - '
9 || MAX(num) range,
10 COUNT(*) cnt
11 FROM data
12 WHERE status='A'
13 GROUP BY grp
14 ORDER BY grp
15 /
RANGE CNT
------ ----------
1 - 3 5
6 - 6 1
9 - 10 2
SQL>
Usando ROW_NUMBER :
SQL> WITH DATA AS
2 (SELECT num - ROW_NUMBER() OVER(PARTITION BY status ORDER BY num) grp,
3 status,
4 num
5 FROM t
6 )
7 SELECT MIN(num)
8 ||' - '
9 || MAX(num) range,
10 COUNT(*) cnt
11 FROM data
12 WHERE status='A'
13 GROUP BY grp
14 ORDER BY grp
15 /
RANGE CNT
------ ----------
2 - 3 2
1 - 2 2
1 - 6 2
9 - 10 2
SQL>
Entonces, en caso de duplicados, el ROW_NUMBER consulta daría resultados incorrectos. Deberías usar DENSE_RANK .
