Utilice una subconsulta correlacionada:
SELECT COUNT(DISTINCT f_bankid) AS tcount
FROM tbl_fileStatus t
WHERE ? = (SELECT f_filestatus FROM tbl_fileStatus WHERE f_bankid = t.f_bankid ORDER BY f_id DESC LIMIT 1)
¿Reemplazar ? con el f_bankid busca.
Vea la demostración
.
En MySql 8.0+ puede usar FIRST_VALUE() función de ventana:
SELECT COUNT(*) AS tcount
FROM (
SELECT DISTINCT f_bankid,
FIRST_VALUE(f_filestatus) OVER (PARTITION BY f_bankid ORDER BY f_id DESC) f_filestatus
FROM tbl_fileStatus
) t
WHERE f_filestatus = ?
Vea la demostración
.
Si desea resultados para todos los f_filestatus en 1 fila:
SELECT
SUM(f_filestatus = 1) AS tcount1,
SUM(f_filestatus = 2) AS tcount2,
SUM(f_filestatus = 3) AS tcount3
FROM (
SELECT t.f_bankid, t.f_filestatus
FROM tbl_fileStatus t
WHERE t.f_id = (SELECT f_id FROM tbl_fileStatus WHERE f_bankid = t.f_bankid ORDER BY f_id DESC LIMIT 1)
) t
Vea la demostración
.
Resultados:
> tcount1 | tcount2 | tcount3
> ------: | ------: | ------:
> 0 | 1 | 2
